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Monday 26 April 2021

TE LAB-TWO STAGE RECIPROCATING AIR COMPRESSOR

 


Ex. No:                                                                                                                                             Date:


 TWO STAGE RECIPROCATING AIR COMPRESSOR

 

Aim: To conduct a test on two stage air compressor and to determine the volumetric efficiency and isothermal efficiency

 

Theory: Air compressors are used for supplying high pressure air. In a multistage, air is compressed in several stages, instead of compressing the air fully in a single cylinder, via the intercooler where air is cooled, to result in saving of work done.

 

Area under the curve in the above PV diagram indicates work done. This PV diagram is for a two stage air compressor with perfect inters cooling I.e., when air sis cooled to intake temperature in the intercooler (T2 – T 1). The low pressure cylinder (LP) diagram is shown as P1 – 1 – 21- P2. High pressure cylinder (HP) diagram is shown as P2 – 2 – 3 – P 3. The reduction of work done due to inter cooling is shown by shaded area 2 – 3 – 3 1 – 2 1. Point 2 lies on the isothermal line 1 – 3”. In case of imperfect inter cooling i.e , when outlet temperature of LP cylinder T2 is not cooled up to inlet air temperature. T1 the point 2 does not lie on the isothermal curve 1 – 3”.

 

Although isothermal compression is economical it is not possible to achieve it in practice. To have an isothermal compression, compressor will have to run extremely slow, while in practice, it is driven at high speeds, so that as much air, as possible is compressed in a given time. Since there is saving of work by compressing air isothermally, it is necessary to make an attempt to obtain approximately and isothermal compression.

 

Procedure:

 

·        Check all electrical connections fill the manometer to zero mark by water

 

·        Start the compressor and allow it to run for few seconds

 

·        Take down the manometer reading, speed indicator  and temperature at no load( zero Pr.)

 

·        At a constant speed of the compressor the delivery pressure From 2.0 kgf/cm2 up to 10.0 kgf/cm2 by varying both the main valve and valve below the storage cylinder i.e, by adjusting in such way that delivery pressure remains at 1.5 kgf/cm2 or so),

 

·        Note the readings of like , speed of the compressor in rpm, manometer readings like, intermediate and delivery pressure, suction air temperature, discharge air temperature etc

 

·        Repeat the trials for different pressure varying from 2.0 to 10.0 kgf/cm2 of the compressor.

 

Observations:



 

Observation table:

S. No.

Inlet

Pressure,

P1

Intermediate Pressure,

P2

Delivery Pressure,

P3

Speed of Compressor,

N

Manometer

Reading,

hm = (h1+h2)

Temperature Reading, oC

Time  for 5 rev of energy meter

 

T1

T2

T3

 

 

 

 

rpm

mm

sec

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Formulae:

·         Area of orifice, a  = πd2 / 4

·         Head of air,    hair = 1000 x hm / ρa

 

Where,     hm = head of water in manometer = h1 + h2

                 ρw = density of water                            = 1000 kgf/m3

                               ρa = density of air at STP         = 1.169 kgf/m3

 

·         Volume of free air delivery, v1 = Cd x aorifice x 2ghair

            Where,      Cd = Coefficient of discharge of orifice = 0.65

                             a   = area of orifice

 

 ·         Swept volume: VLP = Area x Length = πd2l / 4

 

Where,       d = diameter of LP cylinder

l = stroke length of LP cylinder

 

·         Volumetric efficiency:

ηvol = volume of free air delivered / (swept volume of LP cylinder x N/60)

·        Indicated power, IP = IPLPC + IPHPC

            


·        Isothermal Power, Piso = p1.FAD.ln (p2/p1)

·        Isothermal Efficiency, ηvol = Piso / IP

·        Compressor Efficiency, ηcom= IP / Power input from energy meter

                Where, Power input from energy meter (Shaft power) kW-hr

                                    = (3600 x revolutions considered x ηmech x ηtran) / (time x energy meter const.)

Mechanical efficiency, ηmech  = 0.85

Transmission efficiency, ηtran = 0.95


 


 

Pre Lab Questions:

1.   What is the principle of compressor?

2.   Differentiate various types of compressors?

3.   What is the actual thermodynamic process during compression?

4.   Explain concept of multi staging?

5.   What is the necessity of orifice?

6.   What is the pressure control device incorporated in the setup and explain its use.

Post Lab Questions?

1.   Differentiate single stage and multistage compressor?

2.   What is the purpose of an inter cooler in an air compressor?

3.   What is isothermal efficiency?

4.   How do you define volumetric efficiency and isothermal efficiency of a compressor?

5.   Define swept volume.

6.   Plot PV diagram and show how will you calculate the isothermal efficiency?

 

Conclusion:

 

 

PO Attainment:

 

 

 

 

 

 

 

 


Composed By:      

 R.Satheesh, M.E., Asso.Prof.,